Question

In a triangle each of smaller angles is half the largest angle find the an

Answer 1

Let angles be A, B and C
A+B+C=180 (1)

If, each of smaller angles is half the largest angle then
A = B = C/2
also, A = B (2)
and C = 2B (3)
So, by substituting this in (1),
B + B + 2B = 180
4B = 180
B = 45

Now, by (2)
A = B = 45
A = 45

Now, by (3)
C = 2B = 2x45
C = 90

So, the angles of the triangle are 45, 45 and 90