Question

In a Triangle Hypotenuse is 10cm and one of the side is 6cm, then find the length of the remaining

side.​

Answer 1

Answer:

Step-by-step explanation:

Given In right angled triangle the hypotenuse is 10 cm more than the shorter side.if third side is 6 cm less than hypotenuse,find the sides of right angled triangle

Let the length of shorter side be x cm

Now length of hypotenuse is 10 cm more than x, so it will be x + 10 cm

Given length of third side is 6 cm less than hypotenuse , so it will be x + 10 - 6 = x + 4 cm

We know that Pythagoras theorem states that the square on the hypotenuse is equal to the sum of the squares on the other two sides.

So (x + 10)^2 = x^2 + (x + 14)^2

We get  x^2 - 12 x - 84 = 0

We know x = - b ± √b^2 - 4 ac / 2 a

       x = 12 ± √144 + 336 / 2

       x = 16.9 cm

So we get shorter side as 16 .9 cm

Now hypotenuse = x + 10 = 16.9 + 10 = 26.9 cm

and third side = x + 4 = 16.9 + 4 = 20.9 cm

So sides are 16.9 cm, 26.9 cm and 20.9 cm

Answer 2

Answer:

In this que we have to use pgt means Pythagoras theorem

Step-by-step explanation:

(H)²= (P)²+(B)²

10cm=6cm+B

10-6cm= B

4 cm = B

Hence the length of remaining side is4 cm