In a triangle if 3 angle a=4angle b= 6 angle c calculate the angles
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Let x = 3∠A = 4∠B = 6∠C
∠A = x/3
∠B = x/4
∠C = x/6
We know that,in a triangle, the sum of all angles is equal to 180°
∠A + ∠B + ∠C = 180°
x/3 + x/4 + x/6 = 180°
4x/12 + 3x/12 + 2x/12 = 180°
(4x+3x+2x)/12 = 180°
9x/12 = 180°
3x/4 = 180°
x = (180°×4)/3
x = 240°
∠A = x/3 = 240°/3 = 80°
∠B = x/4 = 240°/4 = 60°
∠C = x/6 = 240°/6 = 40°
∠A = x/3
∠B = x/4
∠C = x/6
We know that,in a triangle, the sum of all angles is equal to 180°
∠A + ∠B + ∠C = 180°
x/3 + x/4 + x/6 = 180°
4x/12 + 3x/12 + 2x/12 = 180°
(4x+3x+2x)/12 = 180°
9x/12 = 180°
3x/4 = 180°
x = (180°×4)/3
x = 240°
∠A = x/3 = 240°/3 = 80°
∠B = x/4 = 240°/4 = 60°
∠C = x/6 = 240°/6 = 40°
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