Question

In a triangle if 4 angleA = 3 angle B = 12 angleC find all the angles answer

Answer 1

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It's given that,

⇒ 4∠A = 3∠B = 12∠C

⇒ ∠A = ∠B = ∠C

We know that,

Sum of all the angles of triangle = 180°

⇒ ∠A + ∠B + ∠C = 180°

⇒ 4∠A + 4∠A + 4∠A = 180°

⇒ 12∠A = 180°

⇒ ∠A = 180°/12

⇒ ∠A = 15°

Now, finding the values of rest two angles,

⇒ 4∠A = 3∠B

⇒ 4 × 15° = 3∠B

⇒ 60° = 3∠B

⇒ 60°/3 =∠B

⇒ 20° = ∠B

⇒ ∠B = 20°

⇒ 4∠A = 12∠C

⇒ 4 × 15° = 12∠C

⇒ 60° = 12∠C

⇒ 60°/12 = ∠C

⇒ 5° = ∠C

⇒ ∠C = 5°

∴ The value of ∠A, ∠B & ∠C is 15°, 20° & 5° respectively .

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Answer 2

Answer:

angle A - 15 angle B-20 and angle C- 5