In a triangle if 4LA =3LB=12LC, find the angles.
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Answered by
27
Answer:
<A=67.5
<B=90
<C=22.5
Step-by-step explanation:
- given 4<A=3<B=12<C
- lets consider x= 4<A=3<B=12<C
- so x= 4<A <A= x/4 (i)
- x=3<B <B=x/3 (ii)
- x=12<C <C= x/12 (iii)
- By angle sum property <A+<B+<C=180°
- putting values into eq- x/4+x/3+x/12=180°
- (3x+4x+x) /12=180°
- 8x= 180×12=2160
- x=2160/8=270
- So putting x=270 in eq i ,ii,and iii
- <A=270/4= 67.5
- <B=270/3=90
- <C=270/12=22.5 ans.
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