Question

in a triangle LM||AB. if AL =x-3, AC=2x,BM= x-2& BC = 2x+3, then x =

Answer 1

Answer:

x=-9/7

Step-by-step explanation:

AC/AL=BM/BC [corresponding angles of congruent angles are equal] [∆ABC is congruent to ∆CLM]

x-3/2x=x-2/2x+3

2x(x-2)=(x-3)(2x+3)

2x²+4x=2x²+3x-6x-9

2x²+4x=2x²-3x-9

2x² are cancelled on both sides

4x=-3x-9

4x+3x=-9

7x=-9

x=-9/7

hope this helps you

Answer 2

If you want proof, you can substitute the value of ' x ' in [x+3/x-3=x+5/x-2] if the

ratio of CL/LA=CM/MB is equal, then the value of ' x ' is absolutely correct.

Hope this helps you mate....

Please mark it as brainliest....