Question

In a triangle, one of the angles is equal to half of the sum of the other two angles. if the difference of the other two angles is 40 degrees, then the smallest angle in the triangle is

Answer 1

let A, B and C is angles of triangle
a/c
A=1/2 (B+C)
2A=B+C-------(1)
B-C=40 ------(2)
and also now A+B+C=180-----(3)
now you solve it
(1) put to (3)
3/2 (B+C)=180
B+C=120-----(4)
now (2) and (4)
B=80
C=40
and A=1/2 (B+C)
=60
smallest angle is 40 degree