in a triangle PQR angle P=110 degree , PQ=PR .find angleQ and angle R
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Triangle ∆PQR
Given angle P 110
Then angle of Q and R is
Sum of a triangle is 180
Then taken R and Q as x
180 = x + x +110
180= 2x+110
180 -2x = 110
-2x = 110-180
-2x = -70
X= -70/-2
X = 70/2
X = 35
Angle of R and Q is 35
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Answered by
3
Answer:
Triangle ∆PQR
Given angle P 110
Then angle of Q and R is
Sum of a triangle is 180
Then taken R and Q as x
180 = x + x +110
180= 2x+110
180 -2x = 110
-2x = 110-180
-2x = -70
X= -70/-2
X = 70/2
X = 35
Angle of R and Q is 35
Step-by-step explanation:
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