Question

In a triangle PQR angle P =4/3 angle Q=2 angle R find the measure of the triangle

Answer 1

Answer:

In ΔPQR, ∠P = 2*∠Q and, 2*∠R = 3*∠Q

We know that sum of three angle 180 degree. i.e ∠P + ∠Q + ∠R = 180

∠Q = ∠P/2.............................(1)

And, ∠R = 3*∠Q /2

     or, ∠R = 3*∠P/4...............................(2)

Then, from the values of (1) and (2), ∠P + ∠P/2 + 3*∠P/4 = 180

                                                       Or, ∠P* (1 + 1/2 + 3/4) = 180

                                                       Or, ∠P = 80

From (1), ∠Q = 40 and from (2) ∠R = 60.

Answer: ∠P = 80, ∠Q = 40, ∠R = 60.

Answer 2

Answer:

The answer is 54

Step-by-step explanation:

sum of all angles of a triangle is 180 degree

therefore,

P+Q+R=180

4/3+2+R=180

4+6/3+R=180

10/3+R=180

R= 180×3/10

R=54 degree