In a triangle PQR, angle P =50 degree. The bisectors of angle Q and angle R meet at O. Find angle QOR.
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Step-by-step explanation:
∠QPR=80°
∠PQR+∠QPR+∠QRP=180°
∠PQR+∠QRP=100°
2(x+y)=100°
x+y=50°
So, in △QOR
x+y+∠QOR=180°
∴∠QOR=180°−50°
=130°
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