in a triangle PQR, angle Q =35 degrees angleR=61 degree ,the bisector of angle QPR cutsQR at X.Arrange in decending order PX,QX,RX
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Given:
In a triangle PQR, angle Q =35 degrees angle R=61 degree ,the bisector of angle QPR cutsQR at X.
To find:
Arrange in decending order PX,QX,RX
Solution:
From given, we have,
In triangle PQR,
∠ P + ∠ Q + ∠ R = 180°
∠ P + 35 + 61 = 180°
∠ P + 96 = 180°
∠ P = 180° - 96° = 84°
As the bisector of angle QPR cutsQR at X, so we have,
So, ∠ QPX = ∠ RPX = 84°/2 = 42°
we know that: side opposite to bigger angle is longer
In triangle QPX,
∠ QPX (42°) > ∠ PQX (35°)
so, QX > PX
In triangle CRX,
∠ PRX (61°) > ∠ RPX(42°)
so, PX > RX
so, QX > PX > RX
Therefore, the arrangement in decending order of PX,QX,RX is QX > PX > RX
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