in a triangle pqr angle q is 90 and s is a point on pr such that ps =sr and qs=qr find pqr
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Step-by-step explanation:
Given that:
QP=8cm,PR=6cm and SR=3cm
(I) In △PQR and △SPR
∠PRQ=∠SRP (Common angle)
∠QPR=∠PSR (Given that)
∠PQR=∠PSR (Properties of triangle )
∴△PQR∼△SPR (By AAA)
(II) SPPQ=PRQR=SRPR (Properties of similar triangles)
⇒SP8cm=3cm6cm
⇒SP=4cm and
⇒6cmQR=3cm6cm
⇒QR=12cm
(III)ar(△SPR)ar(△PQR)=SP2PQ2=4282=4
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