Question

In a triangle PQR, angle Q is right angle and value of angle P is x and PQ is 7xm and QR is 24cm find sinx

Answer 1

pr² = 7²+24² = 625 =25²

pr =25

sin x = 24/25 = 0.96

Answer 2

Answer:

The value of Sinx = 24/25

Step-by-step Explanations :

Given : In ∆PQR,

∠Q = 90° & ∠P = x

PQ = 7cm & QR = 24cm

To find : sinx = ?

( Please see the attached document for figure )

In ∆PQR ,

∠Q = 90° & ∠P = x

By applying Pythagoras theorem in ∆PQR, We get,

(PR)² = (PQ)² + (QR)²

(PR)² = 7² + (24)²

= 49 + 576

(PR)² = 625

By taking square root on both sides we get,.

PR = 25cm

We know that,

Sinα = opposite side / Hypotenuse

∴ Sinx = opposite side / Hypotenuse

= QR/PR

Substituting the value in above equation we get,

Sinx = 24/25

Hence the value of Sinx = 24/25