Math, asked by books88e, 2 months ago

In a triangle
PQR, if 3sin P + 4cos Q = 6 and 4sinQ +3cos P =1, then the angle R is equal to​

Answers

Answered by ankitakenganur555
0

Answer:

angle r is equal to 90 degree

Answered by amitsharma777222999
1

Step-by-step explanation:

9sin^2P+16cos^2Q+24sinPcosQ=36

9cos^2P+16sin^2Q+24sinQcosP=1

adding

9+16+24(sinPcosQ+sinQcosP)=37

24sin(P+Q)=37-25=12

sin(P+Q)=1/2

P+Q=30 or P+Q=150

R=180-30=150

or

R=180-150=30

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