Math, asked by arunjatharakonda03, 1 month ago

In a triangle PQR,if 3sinP/4cosQ=6 and 4sinQ+3cosP=1,then the angle R equal to

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Answered by arpitgangwal970

Answer:

3sinP + 4cosQ = 6 … (i) 4sinQ + 3cosP = 1 … (ii) From (1) and (2) ∠ P is obtuse, (3sinP + 4cosQ)2 + (4sinQ + 3cosP)2 = 37 ⇒ 9 + 16 + 24(sinP cosQ + cosPsinQ) = 37 ⇒ 24 sin(P + Q) = 12 ⇒ sin(P + Q) = 1/2 ⇒ P + Q = 5/6 ⇒ R = π/6

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