Question

In a triangle PQR, <P = 90°. If PQ = 6cm and QR = 10 cm, find PR.​

Answer 1

Answer:

In this using pathagoroys theorem

Formula is A^2+B^2=C^2

or C= √A^2+B^2

Step-by-step explanation:

putting value in it

PR=√QR^2+QR^2

=√6^2+19^2

=√136 And

Marked me brilliant