in a triangle pqr PD is perpendicular on QR such that D lies on QR. If PQ=a,PR=b,QD=c and DR=d,prove that (a+b)(a-b)=(c+d)(c-d)
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It shows that (a + b)(a - b) = (c + d)(c - d) is proven in triangle PQR in which PD is perpendicular to QR.
Solution:
As shown in triangle PQR, PD is perpendicular on QR
Now as given in question the value of
PQ = a
PR = b
QD = c
DR = d
To find value of PD:
Now putting the value in
We get
Now equating we get
(a + b) (a - b) =(c + d) (c - d)
Hence proved.
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