Question

In a triangle PQR , PQ= 25CM ,QR=16 CM,RP =?
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Answer 1

Answer

PQ=5cm,PR+QR=25cm

PR=26+QR

IN TRIANGLE PQR, RIGHT ANGLED AT Q,

RP^2=PQ^2+QR^2

(25-QR)^2=5^2+QR^2

625-50QR+RQ^2=25+QR^2

50QR=600

QR=12 cm

PR=13cm

Sin P=P/H=12/13

Cos P=B/H=5/13

Tan P=P/B=5/12

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Let Kanchan have Rs.A in the beginning.

Then,

She spends in the shop =Rs.2A .

Afterwards 31 of 2X is spent on rickshaw.

So, (1−31)rd of 2X is what she is left with.

 (32)×2X is left with her after rickshaw fare. 

 

3X=Rs.20

 

So, she had  Rs.60 in the beginning.