In a triangle PQR , PQ= 25CM ,QR=16 CM,RP =?
Answers
Answered by
8
Answer
PQ=5cm,PR+QR=25cm
PR=26+QR
IN TRIANGLE PQR, RIGHT ANGLED AT Q,
RP^2=PQ^2+QR^2
(25-QR)^2=5^2+QR^2
625-50QR+RQ^2=25+QR^2
50QR=600
QR=12 cm
PR=13cm
Sin P=P/H=12/13
Cos P=B/H=5/13
Tan P=P/B=5/12
Step-by-step explanation:
Answered by
77
Step-by-step explanation:
Let Kanchan have Rs.A in the beginning.
Then,
She spends in the shop =Rs.2A .
Afterwards 31 of 2X is spent on rickshaw.
So, (1−31)rd of 2X is what she is left with.
(32)×2X is left with her after rickshaw fare.
3X=Rs.20
So, she had Rs.60 in the beginning.
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