in a triangle pqr PQ equal to 8 QR is equal to 15 CM find PR the triangle is a right angled triangle at q
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Answered by
11
Answer:
(i) Given:
PQ = 8 cm
QR = 6 cm
PR = ?
∠PQR = 90°
According to Pythagoras Theorem,
(PR)2 = (PQ)2 + (QR)2
PR2 = 82 + 62
PR2 = 64 + 36
PR2 = 100
∴ PR = √100 = 10 cm
(ii) Given :
PR = 34 cm
QR = 30 cm
PQ = ?
∠PQR = 90°
According to Pythagoras Theorem,
(PR)2 = (PQ)2 + (QR)2
(34)2 = PQ2 + (30)2
1156 = PQ2 + 900
1156 - 900 = PQ2
256 = PQ2
∴ PQ = 16 cm
Answered by
11
hey I'm here with your answer:-
PQ =15 cm, QR = 8 cm.
{\bf \underline{ \: To \: Find }} : \: PR
As the triangle is a right angled triangle.
So by Pythagoras theorem
{ PR}^{2} = { PQ }^{2} + { QR}^{2}
{ PR} ^{2} = {15}^{2} + {8}^{2}
{ PR }^{2} = 225 + 64
{ PR }^{2} = 289
PR = \sqrt{289}
PR = 17
Therefore , length of the hypotenuse = 17cm
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