Question

in a triangle pqr PQ is equal to PR and angle Q is twice that of angle P what is the measure of angle Q​

Answer 1

Answer:

Given That:

PQ=PR and ∠Q=2∠P

Since, PQ=PR⇒∠Q=∠R

Now, In △PQR

∠P+∠Q+∠R=180 degree

     (Sum of angles of a triangle is 180 degree )

⇒∠P+2∠P+2∠P=180 degree

⇒5∠P=180 degree

 ⇒P=36 degree  

 ∴∠Q=2∠P=2×36  =72 degree  

 

Answer 2

${{\bold{\underline{\overline{\overline{★Given:-}}}}}}$

PQ=PR

∠Q=2∠P

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∠Q=?

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${{\bold{\underline{\overline{\overline{★By \: Angle \: Property:-}}}}}}$

PQ=PR⇒∠Q=∠R

Now, In △PQR

∠P+∠Q+∠R=180 ∘

(Sum of angles of a triangle is 180 ∘.)

⇒∠P+2∠P+2∠P=180 ∘

⇒5∠P=180 ∘

⇒P=36 ∘

∴∠Q=2∠P=2×36 ∘

=72 ∘

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${{\bold{\underline{\overline{\overline{★Result:-}}}}}}$

∠Q=72 ∘

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