in a triangle PQR,PQ=PR and ∠P=70°. find ∠Q and ∠R
akul2004:
angle Q and R = 65 degree
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If PQ=PR so that ∆PQR Is isosceles Triangle so that suppose ∠R= ∠Q ∠P+∠Q+∠R = 180°
70°+x+x = 180°
70°+2x = 180°
2x = 180°– 70°
2x = 110°
x = 110°/2
x = 55°
Hence Your Answer
70°+x+x = 180°
70°+2x = 180°
2x = 180°– 70°
2x = 110°
x = 110°/2
x = 55°
Hence Your Answer
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