Math, asked by SerenaSmith1483, 11 months ago

In a triangle pqr,pq+qr=14cm,qr+rp=18cms,rp+pq=12cms

Answers

Answered by Tranquilizer
0
let pq be x,qr be y ,rp be z
x+y=14
y+z=18
x+z=12. eq3
y=14-x now solve this and eq3

14-x+z=18=-x+z=4
x+z=12
-x+z=4
solving the equation
2z=16
z=8
x=4
y=10
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