Question

In a triangle pqr,pq+qr=14cm, qr+rp=18cms, rp+pq=12cms .find the radius of the circle which has circumference equals to the perimeter of the triangle

Answer 1

Answer:

R=3.5

Step-by-step explanation:

First do sum of (14+18+12)/2

2*22/7*r=22

R=22*7/22/2

Answer 2

The radius of the given circle whose circumference is equal to the perimeter of the triangle is 3.5 cm.

Given:

pq + qr =14cm

qr + rp =18cm

rp + pq =12cm

To Find:

The radius of the circle whose circumference is equal to perimeter of Δpqr.

Solution:

It is given that, pq+qr=14cm, qr+rp=18cm, and rp+pq=12cm.

Adding all these values, we get

pq + qr + qr+ rp+ rp + pq= 14 + 18 + 12 cm

or, 2 (pq + qr + rp) = 44 cm

or, pq + qr + rp = 22 cm

Now,

Perimeter of Δpqr= pq + qr + rp = 22 cm

We know from the question that,

Circumference of the circle= Perimeter of Δpqr

or, 2 π r = 22 cm

or, r = 22/ 2π = 11/π

or, r = (11 X 7)/22= 7/2

or, r = 3.5 cm

Hence, the radius of the given circle is 3.5 cm.

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