In A Triangle PQR, Right Angled At P, If PQ = 5units, PR = 12 Units And QR = 13 Units, Then The Value Of Tan R Is
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Consider a triangle PQR, right angled at P, in which PQ =
here in question a small mistake is happened .
∆PQR is right angled at R not at P if PQ = 29{hypotenuse}
a triangle PQR, right angled at R, in which PQ = 29 units, QR = 21 units and ∠PQR = θ.
so, PR = √{29² - 21²}
= √{(29-21)(29+21)}
= √{8 × 50}
= 20 unit
(i) cos²θ + sin²θ
from right angled triangle PQR ,
cosθ = QR/PQ = 21/29
sinθ = PR/PQ = 20/29
now, sin²θ = 400/841
cos²θ = 441/841
so, sin²θ + cos²θ = 400/841 + 441/841
= (400 + 441)/841 = 841/841 = 1
(ii) cos²θ - sin²θ
= (21/29)² - (20/29)²
= 441/841 - 400/841
= (441 - 400)/841
= 41/841
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