Question

In a triangle PQR , right angled at Q, if PQ=24 units, QR=10 units , then the value of sin p is equal to

Answer 1

Answer:

given that PQ=24 AND QR=10

FIND PR BY PHYTHOGEORUS THEOREM

PR²=PQ²+QR²

    = 576+100

    = 676

   =√676

PR=26

Sin P = PERPENDICULAR/HYPOTHENUSE

       = 10/26=5/13

SO SIN P=5/13

Step-by-step explanation:

Answer 2

Answer:

5/13

Step-by-step explanation:

opp is 10

adj is 24

hyp= √24^2+10^2 = 26

sinP = opp/ hyp = 10/26= 5/13

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