Question

In a triangle PQR ,right angled at Q.if the length of PQ =63cm and PR =65cm find the length of QR

Answer 1

Using Pythagors Theorem,

(PR)^2 = (PQ)^2 + (QR)^2

(65)^2 = (63)^2 + QR^2

QR^2 = 4225 - 3969

QR^2 = 256

QR = root of 256

QR = 16cm

Answer 2

PR = 65cm = hypotenuse
PQ = 63cm = base
then by Pythagoras theorem ..
${h}^{2} = {p}^{2} + {b}^{2} \\ {p}^{2} = {65}^{2} - {63}^{2} \\ p = \sqrt{ {(65)}^{2} -( {63)}^{2} } \\ p = \sqrt{4225 - 3969} \\ p = \sqrt{256} \\ p = 16$