Question

In a triangle PQR, right angled at Q, PQ equals 24 cm and QR equals 7 cm. S is the midpoint of PR then find QS

Answer 1

Answer:

25 cm

Step-by-step explanation:

first apply Pythagoras theorem to find PR =25 cm

than

aplly THEOREM OF GEOMETRIC MEAN

QS2=PSxSR

=5x5

=25

QS=5 cm

Answer 2

Length of QS =12.5cm

Given:

A triangle PQR, right angled at Q, PQ equals 24 cm and QR equals 7 cm.

S is the midpoint of PR

To find:

Length of QS

Formula used:

Formula of Geometric mean ⇒ (QS)² = PS × SR

Pythagorean theorem  PR² = PQ² +QR²

Explanation:

A triangle PQR, right angled at Q so the adjacent sides are PQ and QR

So from Pythagorean theorem

                PR² = PQ² +QR²

                PR² = 24²+7²

                  PR² = 625

                PR=25

S is the midpoint of PR  ⇒ PS=SR = $\frac{25}{2}$ =12.5cm

       (QS)² = PS × SR

       (QS)² = 12.5 × 12.5

        QS =12.5 cm.

Length of QS =12.5cm

To learn more...

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