in a triangle pqr ,s is the mid point of PR such QS = 1/2PR then angle PQR is
Answers
Given :-
- S is mid point of PR .
- QS = (1/2) PR .
To Find :-
- ∠PQR = ?
Solution :-
Given that,
→ S is mid point of PR .
So,
→ PS = SR = (1/2) PR .
also,
→ QS = (1/2) PR .
then,
→ PS = SR = QS .
now, In ∆QSR we have,
→ QS = SR .
so,
→ ∠SQR = ∠SRQ = Let x . (Angle Opp. to Equal sides are Equal.)
now, in ∆PQS we have,
→ PS = SQ
So,
→ ∠QPS = ∠PQS = Let y . (Angle Opp. to Equal sides are Equal.)
Now, in ∆PQR , we have ,
→ ∠PRQ + ∠PQR + ∠QPR = 180° .(Angle sum Property.)
→ x + (x + y) + y = 180°
→ 2x + 2y = 180°
→ 2(x + y) = 180°
Dividing both sides by 2,
→ (x + y) = 90°.
therefore,
→ ∠PQR = (x + y) = 90° (Ans.)
Hence, angle PQR is equal to 90° .
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