Question

In a triangle PQR. ST is parallel to QR.if PS=4,SQ=6,and PT=2.5,then find TR

Answer 1

Answer:

3.7 cm

Step-by-step explanation:

PS = 4cm

SQ = 6cm

PT = 2.5cm

TR = ?

By B.P.T Theorem we know that, $\frac{AD}{DB} =\frac{AE}{EC}$

Here,

$\frac{PS}{SQ} =\frac{PT}{TR} \\\\\frac{4}{6} =\frac{2.5}{TR}$

TR = 2.5 x 6 / 4   = 15/4 = 3.7

TR = 3.7cm

Answer 2

The value of TR is 3.75 units.

Step-by-step explanation:

Since we have given that

In Δ PQR,

ST is parallel to QR,

So, using "Basic Proportionality theorem": we get that

$\dfrac{PS}{SQ}=\dfrac{PT}{TR}\\\\\dfrac{4}{6}=\dfrac{2.5}{TR}\\\\\dfrac{2}{3}=\dfrac{2.5}{TR}\\\\2TR=2.5\times 3=7.5\\\\TR=\dfrac{7.5}{2}=3.75$

Hence, the value of TR is 3.75 units.

# learn more:

In triangle PQR , ST IS PARALLEL to QR if PT IS 6CM TR IS 18CM SQ IS 15 CM then find PS​

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