Question

in a triangle PQR, T is any point on QR. Prove that 2 PT < (PQ + PR + QR). ​

Answer 1

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Step-by-step explanation:

S is any point on side QR of a ΔPQR. Show that PQ + QR + RP > 2 PS. Use the inequality of a triangle i.e., sum of two sides of a triangle is greater than the third side. Further, show the required result.