Question

In a triangle PQR, the side QR is extended to S. ∠QPR = 72° and ∠PRS = 110°, then the value of ∠PQR is

Answer 1

Hey


So,


∠QPR = 72° and ∠PRS = 110°

∠PQR = ?

∠PRS + ∠PRQ = 180° (LINEAR PAIR)

110° + ∠PRQ = 180°

∠PRQ = 180° - 110°

∠PRQ = 70°

In triangle PQR,

∠QPR +∠PRQ + ∠PQR = 180° (ANGLE SUM PROPERTY)

72° + 70° + ∠PQR = 180°

∠PQR = 180° - 72° + 70°

= 180° - 142°

= 38°


∴ ∠PQR is 38° .

---------------------------------------------------------------------------------------------------

.
.
.
.

Hope this helps!