Question

In a triangle PQR, the three angles are given by (x+5), (x + 10) and (3x + 15). Find the value of x​

Answer 1

Given :

• In a Triangle , the three angles are (x+5) , (x+10) and (3x+15) .

To Find :

• Value of x .

Solution :

As we know that Sum of all three angles of a Triangle is 180° . So ,

$\longmapsto\tt{x+5+x+10+3x+15=180^{\circ}}$

$\longmapsto\tt{5x+30=180^{\circ}}$

$\longmapsto\tt{5x=180-30}$

$\longmapsto\tt{5x=150}$

$\longmapsto\tt{x=\dfrac{150}{5}}$

$\longmapsto\tt\bf{x=30}$

So , The Value of x is 30 .

VERIFICATION :

$\longmapsto\tt{x+5+x+10+3x+15=180^{\circ}}$

$\longmapsto\tt{30+5+30+10+3(30)+15=180^{\circ}}$

$\longmapsto\tt{90+90=180^{\circ}}$

$\longmapsto\tt\bf{180^{\circ}=180^{\circ}}$

HENCE VERIFIED

Answer 2

According to Angle Sum property of Triangle :

The sum of angle of triangle is 180°

Therefore,

X + 5 + x + 10 + x + 15 = 180

5x + 30 = 180

5x = 180 - 30

5x = 150

X = 150/5

X = 30°