Question

In a triangle PQR with right angle at Q,the value of angle P is x, PQ is 7cm, QR is 24cm, then find sinx and cosx

Answer 1

Answer:

see below

Step-by-step explanation:

first find hypotenuse PR=√(24^2+7^2)=25 CM

then sin x=QR/PR=24/25

cos x=PQ/PR=7/25