In a triangle,PQR with right angle at Q. The value of P is 'x',
PQ = 7 cm and QR = 24 cm find cotX.
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Answer:
CotX = 7/24
Step-by-step explanation:
Cot theta = Base/Perpendicular
So, In ∆PQR, we have Base PQ and Perpendicular QR with respect to angle QPR.
Using formula for Cot theta:
CotX = Base/Perpendicular = PQ/QR = 7/24
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