Question

In a triangle PQR with right angle at Q, the value of ∠P is x, PQ = 7 cm and QR = 24 cm, then find sin x and cos x.

Answer 1

by Pythagoras theoram
PR^2= PQ^2+QR^2
= 49 + 576
PR= 25
sin x = 24/ 25
cos x= 7/25

Answer 2

Answer:

pr^2-pq^2=9^2

(pr+pq)(pr-pq)=81

(pr+pq)=81/1=81... (1)

and (pr-pq)=1...... (2)

Step-by-step explanation: