Question

In a triangle PQR with right angle at Q, the value of ZPis x, PQ=7 cm and OR
24 cm, then find sin x and cos x.​

Answer 1

In △PQR

(PQ)

2

+(QR)

2

=(PR)

2

(24)

2

+(7)

2

=(PR)

2

⇒(PR)

2

=576+49=625

⇒PR=25

Now S is the mid point of PR

∴RS=

2

PR

=

2

25

=12.5cm

HERE IS UR ANSWER ,

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