Question

in a triangle right angled b ab =7cm,ac=25cmthen bc ?
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Answer 1

Answer:

AB^2+BC^2=AC^2

AB=7 AC=25

PUT THE VALUES

7^2+BC^2= 25^2

49+BC^2=625

BC^2=576

taking square root we get

BC=14

Answer 2

$\large\mathcal \red \bigstar{\underline{\purple{Given:-}}}$

➛ABC is a right angle triangle.

➛Right angel at B

➛AB=7 cm

➛AC=25 cm

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$\large\bf\blue{\bigstar To\: Find:-}$

Side BC of Triangle.

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$\mathcal \red \bigstar{\underline{\green{FORMULA:-}}}$

$\boxed{Pythagoras\:theorem}$➠

$a {c}^{2} = a {b}^{2} + {bc}^{2}$

$bc = \sqrt{{ac}^{2} - {ab}^{2} }$

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$bc = \sqrt{{(25)}^{2} - {(7)}^{2} }$

$bc = \sqrt{(625 - 49)}$

$bc = \sqrt{576}$

$bc = 24$

$\mathcal \red\bigstar{\underline{\purple{answer}}}\red \bigstar$