in a triangle, side opposite to the larger angle is ...............fill in blank
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Given: A triangle ABC in which ∠B > ∠C
To prove: AC>AB
Proof: Observe that, ∠B>∠C
Therefore, AC is not equal to AB.
If AC=AB implies that ∠B=∠C
Thus either, AC<AB or AC>AB.
Suppose AC>AB, then by the theorem "Suppose two sides of a triangle are not equal. Then the angle opposite to a larger side is 'greater' than the angle opposite to the smaller side".
⟹∠B>∠C, but this contradicts the given hypothesis.
Thus, our assumption is wrong.
Hence, the only possibility left out is AC>AB.
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