Question

In a triangle sum of two angles is equal to third angle and difference between them is 50degree. Find angles

Answer 1

Answer:

Given

a+b=c

& a-b=50

and we know sum of interior angles of a triangle is 180° then

a+b+c=180°

then from from a-b=50 we have a=50+ b then

put this value in a+b=c we get c=50+2b

then put values in a+b+c=180°

so 50+b+b+50+2b=180

then b=20°

then a-20=50 so a=70°

then 20+70+c=180

then c=90°

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Answer 2

Answer:

Angles are 20 70 90

Step-by-step explanation:

the an angle be x

other angle=x+50

third angle=180-(x+x+50)

ATQ

x+x+50=180-(x+x+50)

2x+50+2x+50=180

4x=180-100

x=20

angles are 20, 70, 90

hope this helps you

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