Question

In a triangle the angle s are 2x,(x+30),(x-10).find the angles.

Answer 1

2x+(x+30)+(x-10)=180
4x+20=180
4x=160
x=40

therefore 1st angle=2x=80
2nd angle=70
3rd angle=30

Answer 2

we know,
sum of angles in a triangle =180°
2x+(x+30)+(x-10)=180°
2x+x+30+x-10=180°
(2x+x+x)+30-10=180°
4x+20=180°
4x=180°-20
4x=160°
x=160/40
x=40°
so, 1st angle=2x=2*40=80°
2nd angle=(x+30)=(40+30)=70°
3rd angle=(x-10)=(40-10)=30°....
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