Question

In a triangle the angles are 2x°,(x+30)°,(x-10)° find the angles ?

Answer 1

Hey !!



First angle = 2X°


Second angle = (X + 30)°


And,


Third angle = ( X - 10)° .


We know that sum of angles of a triangle is always equal to 180°.



Therefore,



2X + X + 30 + X - 10 = 180



4X + 20 = 180


4X = 160


X = 40



First angle = 2X = 2 × 40 = 80°.


Second angle = ( X + 30) = 40° + 30 = 70°



And,


Third angle = X - 10 = 40-10 = 30°.

Answer 2

It is given in triangle,

First angle = 2x°
Second angle = (x+30)°
Third angle = (x-10)°

Now,

2x°+(x+30)°+(x-10)° = 180° [Angle Property of a triangle which is 180°].

=> 2x°+x°+30°+x°-10° = 180°
=> 4x°+20° = 180°
=> 4x° = 180°-20°
=> 4x° = 160°
=> x = 160°/4
=> x = 40°

Hence,

first angle = 2x = 2 x 40°= 80°
Second angle =x+30°=40°+30°=70°
&
Third angle = x-10° = 40°-10° = 30°


Be Brainly