Math, asked by sagarvs1998, 1 year ago

In a triangle, the angles are 2xdegrees,(x+30degrees),(x–10degrees) find the angles.

Answers

Answered by sudhanshuraut172
1

Answer:

angle a=80degrees angle b=70degrees and angle c =30 degrees

Step-by-step explanation:

sum all angles= 180 degrees

therefore 2x+x+30+x-10=180

so 4x-20=180

4x=180-20

4x=160

x=160/4

x= 40

threfore a=2*40=80

b= 40+30=70

c=40-10=30

hope it helps


Answered by AsmitaJha
1

Answer:

As we know that,

According to the- Angle sum propert of triangle...

Sum of All the angles of a triangle is 180°


So, as the measure of the three angles are given as---

2x°, x+30° and x-10°


Therefore,

We get,

2x°+x+30°+x-10°=180°

4x+20°=180°

4x=180°-20°

4x=160°

x=160°/4

x=40°


So now, putting the value of x=40°,

We get,

1st angle=80°

2nd angle=70°

3rd angle=30°


So here is your answer.

Hope it helps you.

And if it does then plz mark as brainliest!!!



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