Question

in a triangle the average of any two side is 6 CM more than the half of the third side find the area of the triangle in square centimetre

Answer 1

Let the sides of the triangle be a cm,b cm and c cm.a+b−c=a+c−b=b+c−a=6⇒a+b−c+a+c−b+b+c−a=18⇒a+b+c=18 cmArea of triangle=(a+b+c2)(a+b+c2−a)(a+b+c2−b)(a+b+c2−c) ‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√=(a+b+c2)(b+c−a2)(a+c−b2)(a+b−c2)‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√=1418×6×6×6‾‾‾‾‾‾‾‾‾‾‾‾‾‾√=93‾√cm2

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Answer 2

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