In a triangle, the average of any two sides is 6 cm more than half of the third side, then find
the area of the triangle (in sq. cm)
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let a,b,c are 3 Sides
so , a+b-c=6
a+c-b=6
b+c-a= 6
add all three questions
a+b+c= 18.
a+b = b+6 (given
so , 2c= 12
c= 6
and So , a&b = 6
hence ,it is an equilateral triangle
so, area = √3/4×6²
= 9√3 ans.
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