Question

in a triangle the first angle is 20% more than the third angle.second angle is 20% less than the third angle.find the smallest angle of the triangle?

Answer 1

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Answer 2

Let third angle be x

From the question we interpret:

Angle A = x+(20x/100)

Angle B=x-(20x/100)

Therefore to find the angles:

x+x+(20x/100)+x-(20x/100)=180°

Solving this we get x=60°

Or third angle =60°

First angle=60+(20*60/100)=72°

And second angle:180°-(72°+60°)=48°

So smallest angle is 48°