In a triangle the greatest angle is 20 degrees more than twice the middle angle and the smallest angle is 40 find all the angles
Answers
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Given,
Smallest angle = 40 °
Greatest angle = 20 ° + x
Let middle angle be x
=))Sum of all angles of a triangle is 180°
Now,
(20 + x) + x + 40° = 180°
=) 20° +2x + 40° = 180°
=) 60° + 2x = 180°
=) 2x = 180-60
=) 2x = 120
=) x = 60°
Hence,
Greatest angle =) 20 + 60 = 80°
Middle angle =) 60°
Smallest angle =) 40°
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Let verify the answer!
80° + 60 ° + 40 ° = 180°
180 ° = 180 °
LHS = RHS
hence, proved ✔
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✌✌
let, the middle angle=x
greatest angle=20°+2x
smallest angle= 40°
sum of all angles of a triangle=180°
40°+20°+2x+x = 180°
60° + 3x = 180°
3x = 120°
x = 40°
largest angle=20°+2×40°
=20°+80°=100°
middle angle=40°
So, angles are 40°,40°,100°