in a triangle the height is double the base and area is 400 sq.cm .Find the length of base and height
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Area=1/2*b*h
Let h and b be x
400cm²=1/2*x*x
800cm²=x²
20 underoot 2=x
Height is double the base
Base=20 underoot 2
Height=40 underoot 2
Let h and b be x
400cm²=1/2*x*x
800cm²=x²
20 underoot 2=x
Height is double the base
Base=20 underoot 2
Height=40 underoot 2
Sayalee07:
Area of triangle ABC is given 400cm sq.
This is wrong
Answered by
3
Let base be b
Let height be h
Then a/q,
h=2b..... (1)
AREA = 1/2 × b × h
400= 1/2 × b × 2b.... [using (1)]
400= b^2
b = root400
b= 20
So, Base = 20 cm
Height = 2×20= 40 cm
Please mark it brainliest if it helped!
Let height be h
Then a/q,
h=2b..... (1)
AREA = 1/2 × b × h
400= 1/2 × b × 2b.... [using (1)]
400= b^2
b = root400
b= 20
So, Base = 20 cm
Height = 2×20= 40 cm
Please mark it brainliest if it helped!
Yes ur answer is write. ...I looked at the brainliest answer now but it is solved wrongly and I was not able to answer this question because of technical problem
Nice excuse
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