Question

in a triangle the height is double the base and the area is 400cm^2.find the length of the base and height​

Answer 1

$Let \: base \:of \: a \: triangle (b) = x \:cm$

$Height (h) = 2x \:cm$

$Area \:of \:the \: triangle = 400 \:cm^{2}$

$\implies \frac{1}{2} \times b \times h = 400$

$\implies \frac{1}{2} \times x \times 2x = 400$

$\implies x^{2} = 400$

$\implies x = \sqrt{400}$

$\implies x = \sqrt{20^{2}}$

$\implies x = 20 \:cm$

$base \:of \: a \: triangle (b) = x = 20 \:cm$

$Height (h) = 2x \:cm= 2 \times 20 \\= 40 \:cm$

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Answer 2

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ANSWER :

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The Base of the Triangle = b

The Height of the triangle, h = 2b

The Area of the triangle, A = 400 cm^2

We know that ,

$area \: of \: triangle \: = \frac{1}{2} \times b \times h$

From this ,,,

Area , A = 1/2 × b × 2b

400 = b^2

b = ( 400)^1/2

b = 20cm

The height of the triangle, h = 2b

h = 2 × 20

h = 40 cm

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