in a triangle the height is double the base and the area is 400 CM square find the length of the base and height
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Answer:
base is 20 and highest is 40
Step-by-step explanation:
senior70:
explantion pls
pls give step by step explanation
2×base(b) = height(h)
Area of triangle = 1/2 × b × h
= 1/2 × 2b × b
b × b i.e b square = 400
b = square root of 400 = 20cm
h = 2 × b = 20 × 2 = 40cm
= b = 20cm ; h = 40cm
Area of triangle = 1/2 × b × h
= 1/2 × 2b × b
b × b i.e b square = 400
b = square root of 400 = 20cm
h = 2 × b = 20 × 2 = 40cm
= b = 20cm ; h = 40cm
Answered by
4
2×base(b) = height(h)
Area of triangle = 1/2 × b × h
= 1/2 × 2b × b
therefore, b × b i.e b square = 400 (given area)
therefore b = square root of 400 = 20cm
therefore h = 2 × b = 20 × 2 = 40cm
therefore answer = b = 20cm ; h = 40cm
Area of triangle = 1/2 × b × h
= 1/2 × 2b × b
therefore, b × b i.e b square = 400 (given area)
therefore b = square root of 400 = 20cm
therefore h = 2 × b = 20 × 2 = 40cm
therefore answer = b = 20cm ; h = 40cm
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