Question

in a triangle the middle of the angle are X degree (X + 20) degree and ( X) . find the angle​

Answer 1

Answer:

Sum of angles in a triangle = (n-2)× 180° where n is the number of side

Number of sides in a triangle = 3

Sum of interior angles=( 3-2)× 180° = 180°

Given that,

1st angle = x°

2nd angle (x - 20)°

3rd angle = (x-40)°

So, an equation will be formed

x° + x° - 20° + x° - 40° = 180°

regrouping the terms in LHS ,

we have,

x° + x° + x° - 20° - 40° = 180°

3x° - 60° = 180°

3x = 180° + 60°

3x = 240°

x = \frac{240}{3}x=

3

240

x = 80

So,

1st angle = x = 80°

2nd angle = x -20° = 80° - 20° = 60°

3rd angle = x - 40° = 80° - 40° = 40°

Thus,

the angles of the given triangle 80° , 60° and 40°